in the net ionic equation is: 5. Regeneration of copper metal: mass of regenerat
ID: 702617 • Letter: I
Question
in the net ionic equation is: 5. Regeneration of copper metal: mass of regenerated copper s mass of watchglass (g) mass of regenerated copper (g) mass of zinc metal (g) 2 59watchglass (g) 12 o a. Calculate your percent yield as the mass of regenerated copper compared to the initial mass of copper b.fyour percent yield was less than 100 %, describe two specific steps in the procedure during which you might have lost copper. If your percent yield was more than 100 % suggest one possibility to account for this. July 12, 2017 page 4-8
Explanation / Answer
Ans 6.33
Side of cube = 5 cm*1m/100cm = 0.05 m
surface area of one face of cube
A = (0.05 m)²
A = 0.0025 m²
Weight of cube = m x g
W = (1 kg) × (9.81 m/s²)
W = 9.81 N
Downward pressure
P = W / A
P = (9.81 N) / ( 0.0025 m²)
P = 3924 Pa
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