in the first question we use different way to calculate h-bar but in the second

Question

in the first question we use different way to calculate h-bar but in the second question's solution we used different way to calculate h-bar why is it so?

HYDROSTATIC PRESSURE EXAMPLE 3.21 A eireular plate of 3 m diameter is under water with its plane making an angle of 30 with water surface. If the top edge of the plate is 1 m below the water surface, find the force on one side of the plate and its location Solution: Given d#3m CB= 1m #1+1.5×0.5#175 m FIG. 3.26 Area ofthe plate. A ,L 07 m: 64 64 Force, p's "A 9810 07 x 1.73 0121374.23 N·121.37 KN Ans. -depth of centre of pressure san' 398x(san 307' 1.75 707×1.75 .008+1.75 m 183 m Ans. Circle 2 64 d/2

Explanation / Answer

in the first question the h bar is calculated using the formula
h bar = DM + ME
Now DM = CB = 1 m
ME = EBsin(30) = dsin(30)/2 = 3sin(30)/2 = 0.75 m
hence h bar = 1.75 m

in second question, if h bar is found by the method of previous part
h bar = 1 m + 3*sin(theta)/2
now sin(theta) = (x ) / (3/2) = (2 - 1)/(3)
sin(theta) = 1/3
hence
hbar = 1 + 3*1/2*3 = 1.5 m is the same as h b ar found inthis problem by other method

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.