1.(40 points) Perform the following pressure conversions, assuming when necessar

Question

1.(40 points) Perform the following pressure conversions, assuming when necessary that atmospherie pressure is 1 atm. Unless otherwise stated, the given pressures are absolute. a. 2600 mm Hg to psi b. 275 ft-H:O to kPa c. 3.00 atm to N/em d. 280 cm-Hg to dyne/m2 e. 25.0 psig to mm-Hg (gauge) f. 25.0 psig to mm-Hg (absolute) g. 325 mm-Hg to mm-Hg gauge h. 35.0 psi to cm of carbon tetrachloride. 2. (30 points) Convert the temperatures in parts (a) and (b) and temperature intervals in parts (c) and (d): 3. (30 points) Fill in the values in the blanks in the following: a. Consider a tank that is to take a pressure of 10 psi. This is equivalent of (approximately) b. It may help to remember that 14.7 psi ( c. If your automobile tires take 24 psi of air, you will have to set the air-pump pressure to (N/m), or (kN/m2), or (kPa) atm) kN/m2) or approximately MN/m) kN/m'); if you need 26 psi, the pressure will be k. d. An absolute pressure of 10 micro m-Hg is almost exactly equivalent to N/m), or Pa).

Explanation / Answer

Ans 1

Part a

Convert 2600 mmHg to psi

= (2600 mmHg) x (1 atm / 760 mmHg) x (14.7 psi / 1 atm)

= 50.289 psi

Part b

Convert 275 ft H2O to kPa

= meters of H2O x density of water x g

= (275 ft) x (1 m / 3.281 ft) x (1000 kg/m3) x (9.81 m/s2)

= (822234.075 Pa) x ( 1 kPa/1000 Pa)

= 822.234 KPa

Part c

Convert 3 atm to N/cm2

=( 3 atm) x (101325 Pa / 1atm) x (1N/m2 / 1Pa)

= (303975 N/m2) x (1m/100cm)2

= 30.3975 N/cm2

Part d

Convert 280 cm Hg to dyne/m2

= meters of Hg x density of Hg x g

= (280 cm) x (1 m / 100 cm) x (13600 kg/m3) x (9.81 m/s2)

= (373564.8 N/m2) x (10^5 dynes/1N)

= 3.735 x 10^10 dynes/m2

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.