3· (35 points) The system shown below is a continuous process running at steady-

Question

3· (35 points) The system shown below is a continuous process running at steady-state. Stream 3 36 g A/s Stream 5 F5 g/s 0.50 g A/g 0.50 g B/g Stream 7 0.10 g B/g Y7 g C/g Stream 1 0.60 g A/g 0.40 g B/g Unit 1 Stream4 Unit 2 fP4 g/s Stream 6 Stream 8 -L-FausNg 1 X4gB//g Y4 g C/g Z4 g D/g Unit 3 | F8 g/s 0.00 g B/g 0.00 g A/g 0.25 g C/g Stream 2 0.0 gA/g X6 g B/g Y6 g C/g Z6 g D/g 0. F2 g/s 0.25 g B/g 0.375 g D/g 28 gDig a. Indicate if the statement is true (T) or false (F) (6 pts): i) Unit 1: The value of F1 > 36TF ii) Unit 1, component B: 0.40 + 0.25 = X4 41.-F i) Unit 3: Z8-Z6, since there is no D in stream 7F iv) The fractions of component B in all the streams should sum to 1.00TF b. Perform a degree of freedom analysis (5 pts) Degree of Freedom Analysis Un it 1 Unit 2 Unit3 System Overall # of unknowns # of MB eqns. # of add. Eqn Degree of Freedom 0 3 c. Write a mass balance for component B on unit 2 (4 pts) d. Write a mass balance for component A on unit 1 (4 pts) e. Write a mass balance for component C on unit 3 (4 pts) f. Write an overall total mass balance (4 pts) F2-36 -F-F -F o g. Write an overall balance for component A (4 pts) h. Write a mass balance for component A for unit 1 and unit 2 combined. (4 pts)

Explanation / Answer

Part a

i) true

unit 1

Overall Material balance of unit 1

F1 + F2 = F3 + F4

F1 + F2 = 36 + F4

Component A balance

F1 x 0.60 = 36 + F4 x W4

F1 = 60 + F4W4/0.60

To be true the above equations

F1 > 36

ii) false

Component B Balance of unit 1

F1 x 0.40 + F2 x 0.25 = F3 x 0 + F4 x X4

F1 x 0.40 + F2 x 0.25 = F4 x X4

iii) false

Material balance of D in unit 3

F6 x Z6 = F7 x 0 + F8 x Z8

F6 x Z6 = F8 x Z8

iv) false

Fraction of all components in any of the stream should sum = 1

Not a component in all the streams.

PART C

Component B Balance of unit 2

F4 * X4 = F5 * 0.50 + F6 * X6

F4 * X4 - F5 * 0.50 - F6 * X6 = 0

Part d

Component A balance on unit 1

F1 x 0.60 = 36 + F4 x W4

F1 x 0.60 - 36 - F4 x W4 = 0

Part e

Mass balance of C in unit 3

F6 * Y6 = F7 * Y7 + F8 * 0.25

F6 * Y6 - F7 * Y7 - F8 * 0.25 = 0

PART G

Overall Material balance of A

F1 * 0.6 = 36 + F5*0.5 + F8*0

F1 * 0.6 - 36 - F5*0.5 = 0

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