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Desperately need help with the “Chemical Engineering Calculations II” Problem -

ID: 701700 • Letter: D

Question

Desperately need help with the “Chemical Engineering Calculations II” Problem - #1 (a, b, and c) A.S.A.P. Please show work by providing the steps that led up to the answer shown in BOLD. Thank you in advance for your time and support!


Reminder: Even though answers for a, b, and c were provided in BOLD, I’m having a hard time trying to figure out the steps on how these were derived and need help.

Problem I Air at 50% relative humidity is cooled at constant pressure of l atrn from 90 °C to 25 °C, a. Estimate the dew point and degrees of superheat of the air at 90 °c. b. How many moles of water condense per cubic meter of feed gas? (see example 6.3-2) c. Suppose a sample Ans. Tdp 72.7 °C; Degrees of Superheat- 17.3 oC Ans. 21.6 mol HO condense/m3 and the pressure is raised at constant temperature until a mist forms on the mirror. At what of the 90 °C air is put in a closed variable-volume chamber containing a mirror, pressure would the mist form? Assume ideal gas behavior. Ans. P-2.00 atm

Explanation / Answer

a.dew point

Tdp F=TF - 9/25(100-RH)

   =181-9/25(100-50)

   =163f=72.7 c

Dew point

It is calculate on the basis of Intel temperature minus dewpoint temperature

    90-72.7=17.3 c

b)pH20=262.9 MMhG

YH20=pH20/P

=0.346 at 90 c

How much water in air at 25 c

pH20=23.76 mmHG

yH20=PH20/P

       =0.031 at 25 c

n=PV/RT

nH20 AT 90 C=22.8

nH20 AT30 C=1.27

n H20 Cond =21.6 mol

C)IDEAL GAS LAW

PV = nRT

P=nRT/V

T=90= 363 K

R=0.0821

v==14.9 volume

Pressure =nRT / V = 0.0821*363/14.9 =2 atm

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