HW #5 Due date: Wed, 2/14 1) One hundred kilograms of water at T-50 °C and P-40.
ID: 701351 • Letter: H
Question
HW #5 Due date: Wed, 2/14 1) One hundred kilograms of water at T-50 °C and P-40. Bar is heated to produce saturated steam at the same pressure, How much heat is needed? Hint: will need steam tables 2) A piston-cylinder assembly contains water vapor at a pressure of 30 psi and a volume of1 ft. The vapor is heated at constant pressure until its volume doubles. Determine the work and heat transfer. 3) (problem 3.101 from book) A tank contains 0.5 m3 of nitrogen (N2) at -71 °C and 1356 kPa. Determine the mass of nitrogen, in kg, using a) Ideal gas model b) Compressibility chart Do the answers differ in this case? 4) Ammonia gas is at a pressure of 150 atm, a temperature of 210 °C, and has a molar flow rate of 5 mol/min. Determine the volumetric flow rate by using the compressibility equation of state. (Note: Tc-405.5 K, Pc 111.3 atm) 5) A three-liter tank contains two gram-moles of nitrogen at - 150.8 °C. Estimate the tank pressure using the the virial equation of state truncated after the second term. The constant B(T) in the virial equation is -0.112 L/mol.Explanation / Answer
Answer to question number 1
mass of water = 100 Kg
P = 40 bar , T = 50 oC
we will make use of steam table
Enthalpy of steam at these temperatures and pressure (H1) = 212.772 KJ/Kg
now we need saturated steam at the same pressure that is 40 bar
Saturated steam enthalpy of vapor at 40 bar = 2800.897 KJ/Kg
Net amount of heat required = H1 -H1 =2800.897 - 212.772 = 2588.125 KJ/Kg
now for 100 KJ, amount of steam heat required = (2588.125 KJ/Kg) *100 = 258812.5 KJ
FINAL ANSWER : Amount of heat needed is 258812.5 KJ
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