moles of NaH2A = 2.58 / 215 = 0.012 moles of NaOH = 0.60 / 40 = 0.015 frist reac

Question

moles of NaH2A = 2.58 / 215 = 0.012

moles of NaOH = 0.60 / 40 = 0.015

frist reaction:

NaH2A   + NaOH ---------------------------> Na2HA + H2O

0.012          0.015                                       0              0

0                 0.003                             0.012          0

second reaction:

Na2HA   + NaOH -------------------------> Na3A + H2O

0.012       0.003                                       0          0

0.009           0.0                                      0.003      -

pH = pKa3 + log [Na3A / Na2HA]

pH = 6.40 + log (0.003 / 0.009)

pH = 5.92

Explanation / Answer

10. To 2.58 g of sodium citrate (NaH2A, MW-215) in 100 ml of water is added 0.60 g of NaOH (MW 40) What is the pH of the resuting solution? pKal = 3.13 pKa=4.76 pKo = 6.40 (6pt)

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.