Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

moles of NaoH required to reach the final equivalence point? Titration of a Poly

ID: 580446 • Letter: M

Question


moles of NaoH required to reach the final equivalence point?

Titration of a Polyprotic Acid Approved Record your titration data directly onto the back of this sheet. Show your calculations on a separate sheet of paper Data, Calculations, and Conclusions 1. Concentration of NaOH solution 2. Mass of acid used 3. a. Number of equivalence points (from graph) ,10 0 m b. This acid is monoprotic /diprotic General formula of the acid (in the form of HnA)-2-- In the space below write a balanced chemical equation for the complete neutralization reaction / triprotic (circle one) 4. 5. 6. Volume of NaOH solution required to reach the final equivalence point 33, 7. Moles of NaOH required to reach the final equivalence point 8. Moles of acid neutralized 9. Molar mass of the acid 10. Write equations for the stepwise ionization of each acidic proton in the unknown acid followed by the value of the pKa of each step as determined from your graph. Note: These equations are not neutralizations and, therefore, do NOT include NaOH or OH 105

Explanation / Answer

As from the data the concentration of the NaOH is=.1 M and 33.20 mL of 0.1 M NaOH is reuired.

now,

as no of moles 0.1 M NaOH in 1000mL solution is=0.1 moles

then, no of moles of NaOH at the final equivalence point is= (33.20 * 0.1)/1000

= 3.32*10-03 moles