10. Se atomic number is 34 So it has 34 electrons. Two electrons are added to Se
ID: 700172 • Letter: 1
Question
10. Se atomic number is 34
So it has 34 electrons. Two electrons are added to Se atom and become Se-2. So it has totally 36 electrons. It resembles Kr (36) configuration.
Answer is D.
11. Cr electronic configuration is [Ar] 4s1 3d 5
Remove 3 electrons to get [Ar] 3d3
Answer is D.
12. Halogens have totally 7 electrons
Answer is E) 7
13. Answer is B. Core electrons effectively shield outer electrons from nuclear charge.
14. In periods atomic raddi decreases
Ba> P > Cl
Answer is C.
15. N -1402 KJ
F - 1681 KJ
As - 947 KJ
So order is F > N > As
Answer is B
16. C
Higher the charge leser will be the size.
Explanation / Answer
10. Give the ground state electron configuration for Se2-(2 pts.) A) [Arj4s23d104p4 B) [Ar]4s23d104p2 C) [Arj4s24p6 D) [Ar)4s23d104p6 E) [Ar]4s23d84p6 11 . Choose the ground state electron configuration for Cr" (2 pts.) A) [Ar]4s13d2 B) [Ar] C) [Ar]4s23d6 D) [Ar]3d3 E) [Arj4s23dl 12. How many valence electrons do the halogens possess? (2 pts.) A) 5 B) 6 C) 2 D) 1 13·Choose the statement that is TRUE. (2 pts.) A) Outer electrons efficiently shield one another from nuclear charge. B) Core electrons effectively shield outer electrons from nuclear charge. C) Valence electrons are most difficult of all electrons to remove. D) Core electrons are the easiest of all electrons to remove. E) All of the above are true. 14. Place the following elements in order of increasing atomic radius. (2 pts.) Ba Cl C)CI
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