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3. Titration pKa2 = 14 - pKb1 = 4.27 pKa1 = 14 - pKb2 = 1.25 a. Initial [C2O4^2-

ID: 700132 • Letter: 3

Question

3. Titration

pKa2 = 14 - pKb1 = 4.27

pKa1 = 14 - pKb2 = 1.25

a. Initial

[C2O4^2-] = 0.0655 M

C2O4^2- + H+ <==> HC2O4- + OH-

let x amount reacted

Kb1 = [HC2O4-][OH-]/[C2O4^2-]

1.84 x 10^-10 = x^2/0.0655

x = [OH-] = 3.48 x 10^-6 M

pOH = -log[OH-] = 5.46

pH = 14 - pOH = 8.54

b. after 2.00 HCl added

initial C2O4^2- = 0.0655 M x 16 ml = 1.048 mmol

added HCl = 0.17 M x 2 ml = 0.34 mmol

formed HC2O4- = 0.34 mmol

remaining C2O4^2- = 0.708 mmol

pH = pKa2 + log(C2O4^2-/HC2O4-)

     = 4.27 + log(0.708/0.34) = 4.60

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after 8.00 HCl added

initial C2O4^2- = 0.0655 M x 16 ml = 1.048 mmol

added HCl = 0.17 M x 8 ml = 1.36 mmol

formed H2C2O4 = 0.312 mmol

remaining HC2O4- = 0.736 mmol

pH = pKa1 + log(C2O4^2-/HC2O4-)

     = 1.25 + log(0.736/0.312) = 1.63

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after 20.00 HCl added

initial C2O4^2- = 0.0655 M x 16 ml = 1.048 mmol

added HCl = 0.17 M x 20 ml = 3.4 mmol

This is past second equivalence point

excess [HCl] = [H+] = 1.304 mmol/36 ml = 0.0362 M

pH = -log[H+] = -log(0.0362) = 1.44

c. pH at first equivalence point

pH = 1/2(pKa1 + pKa2) = 1/2(1.25 + 4.27) = 2.76

pH at second equivalence point

volume HCl added = 2 x 0.0655 M x 16 ml/0.17 M = 12.33 ml

[H2C2O4] formed = 1.048 mmol/28.33 ml = 0.037 M

H2C2O4 + H2O <==> HC2O4- + H3O+

let x amount reacted

Ka1 = [HC2O4-][H3O+]/[H2C2O4]

0.0562 = x^2/0.037

x = [H3O+] = 0.0456 M

pH = -log[H3O+] = 1.341

d. plot, volume of HCl (ml) on x-axis and pH on y-axis (file not uploading)

e. Indicator for this titration would be thymol blue for first equivalence and methyl orange for the second equivalence point detection. Best indicator should have color change in the region of equivalence point.

Explanation / Answer

3. A 16.00 mL aqueous solution of a 0.0655 M, sodium oxalate (Na2C204, pKbi -9.734, pKb2 12.750) is titrated with 0.170 M HC1. a. b. c. d. e. What is the initial pH of this solution? Calculate the pH of the solution after 2.00, 8.00, 20.00 mL of HCI is added. Calculate the pH at the equivalence point(s). Sketch the titration curve for this titration. Select appropriate indicator(s) for this titration.

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