6.a) weight of organic compound = 0.6908 g 44 grams of CO 2 contains 12 grams of
ID: 700079 • Letter: 6
Question
6.a)
weight of organic compound = 0.6908 g
44 grams of CO2 contains 12 grams of 'C'
1.7604 g of CO2 contains --? grams of 'C' = (12/44) x 1.7604 = 0.4801 g
18 grams of H2O contains 2 grams of 'H'
0.4504 g of H2Ocontains --? grams of 'H' = (2/18) x 0.4504 = 0.05 g
weight of 'O' in the compound = Total weight - (wight of 'C' + weight of 'H')
= 0.6908 - (0.4801 +0.05) = 0.6908-0.5301 = 0.1607 g
6.b) C H O
weights in the compound (g) 0.4801 0.05 0.1607
weight/ atomic weight 0.4801/12 0.05/1 0.1607/16
0.04 0.05 0.01
Ratio of C,H and O in the compound = 4:5:1
Empirical formula = C4H5O
Explanation / Answer
0.6908 g of an organic compound containing only C, H, and O was burned in excess of pure O2, producing 1.7604 g of CO2 and 0.4504 g of H2O.
6.a) Calculate the number of grams of C and H in the combustion products and therefore in the 0.6908 g of the compound. Also calculate the number of grams of O in the 0.6908 g. Show your work.
6.b) What is the empirical formula of this compound?
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