N2(g) + 3H2(g) ---------------------> 2NH3(g) 1 mole of N2 react with 3moles of

Question

N2(g) + 3H2(g) ---------------------> 2NH3(g)

1 mole of N2 react with 3moles of H2

4 molecules of N2 react with = 3*4/1 = 12 molecules of H2

   H2 is limiting reactant

3 moles of H2 react with N2 to gives 2 moles of NH3

9 molecules of H2 react with N2 to gives = 2moles*9moleules/3molecules = 6 molecules of NH3

from balanced equation

3 moles of H2 react with 1 mole of N2

9 molecules of H2 react with = 1*9/3 = 3 molecules of N2 is required.

N2 is excee reactant

The molecules of N2 reamins   = 4-3 =1 molecules of N2

H2 is limiting reactant.

The molecules of H2 reamins = 0

Explanation / Answer

able Print 2 of 5 Calculator Periodic T Sapling Learning Nitrogen and hydrogen combine at high temperature, in the presence of a catalyst, to produce ammonia. N,(g)+3H2(g) 2NH,(e) Assume 4 molecules of nitrogen and 9 molecules of hydrogen are present Number Aftercomplete reaction, how many molecules of ammonia are produced? Number OBel How many molecules of H2 reman? Number How many molecuies of N2 remain? O nitrogen O hydrogen What is the limiting reactant? Hint F8

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