PART A: The reaction is expressed as P 4 + O 2 = P 2 O 5 The balanced chemical r

Question

PART A:

The reaction is expressed as
P4 + O2 = P2O5

The balanced chemical reaction equation is
P4 + 5O2 = 2P2O5

In the above balanced reaction equation; 1 mole of P4 produces 2 moles of P2O5.

Now,

Molar mass of P4 = 123.90 g/mol
So, 123.90 g of P4 = 1 mol
or, 1 g of P4 = (1/123.90) mol
or, 136 g of P4 = (136/123.90) mol = 1.1 mol

Since, 1 mole of P4 produces 2 moles of P2O5.
or, 1.1 mole of P4 produces (1.1 x 2) moles of P2O5.
or, 1.1 mole of P4 produces 2.2 moles of P2O5.

PART B:

The reaction is expressed as
P4 + O2 = P2O5

The balanced chemical reaction equation is
P4 + 5O2 = 2P2O5

In the above balanced reaction equation;
5 mole of O2 produces 2 moles of P2O5.
1 mole of O2 produces (2/5) moles of P2O5.

Now,

Molar mass of O2 = 32 g/mol
So, 32 g of O2 = 1 mol
or, 1 g of O2 = (1/32) mol
or, 144 g of O2 = (144/32) mol = 4.5 mol

Since, 1 mole of O2 produces (2/5) moles of P2O5.
or, 4.5 mole of O2 produces (4.5) x (2/5) moles of P2O5.
or, 4.5 mole of O2 produces 1.8 moles of P2O5.

Explanation / Answer

ntProblemiD 90925799 onsider a situation in which 136 g of P4 are exposed to 144 g of 02 Part A What is the maximum amount in moles of P2Os that can theoretically be made from 136 g of P4 and excess oxygen? Express your answer to three significant figures and include the appropriate units Hints Value Units Submit My Answers Give Up Part B What is the maximum amount in moles of P2Os that can theoretically be made from 144 g of O2 and excess phosphorus? Express your answer to three significant figures and include the appropriate units Hints Value Units Submit My Answers Give Up Part C This question will bo shown after you complele previous question(s)

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.