PART A. In figure above, the force F2=15.0N acts at the point 70.0 cm. What is t
ID: 1456923 • Letter: P
Question
PART A. In figure above, the force F2=15.0N acts at the point 70.0 cm. What is the magnitude of the torque due to F2 about an axis through point B and perpendicular to the page? Is the torque clockwise or is it conterclockwise? Show your work and give correct units.
PART B. In the figure above, what is the magnitude of the net torque due to both forces F1 and F2 about an axis perpendicular to the page through point A? is it clockwise or counterclockwise? Show your work and include the correct units.
10 50 70 F1 = 10.0 N F2 = 15.0 N Meter stick with 2 forces acting at pointsExplanation / Answer
A)
torque due to F2 about point B = F2*r*sin(90)
= 15*0.2*1
= 3 N.m <<<<<<<-----------Answer
It is clockwise torque.
B) Torque deu to F1 and F2 about point A = F1*r1*sin(90) + F2*r2*sin(90)
= 10*0.1 + 15*0.7
= 11.5 N.m <<<<<<<-----------Answer
It is clockwise torque.
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