Moles of helium gas= 14 moles, molesof Argon gas= 20 moles, total moles = moles

Question

Moles of helium gas= 14 moles, molesof Argon gas= 20 moles, total moles = moles of helium+ moles of Argon= 14+20=34, mole fractionof Argon= moles of Argon/total moles= 14/34=0.412

Partial pressure of argon= total pressure* mole fraction of Argon= 0.412*7.8 =3.2136 atm

mass of Xenon added = 440 gm, moles of Xenon= mass/atomic weight = 440/131.3=3.35 moles

total moles of gas after addition =34+3.35= 37.35 moles

since volume remained constant leading to increase in pressure. the gas law at constant temmperaute

n1/P1= n2/P2

where n1= 34 and n2= 37.35 and P1= 7.8 atm

P2= n2P1/n1= 37.35*7.8/34=8.6 atm

Volume of gas, V= n1RT/P1, R= 0.0821 L.atm/mole.K, n1= 34 T1=55 deg.c= 55+273= 328K

V= 34*0.0821*328/7.8=117.3 L

2. mass of helium= 10ug= 10*10-6 gm, atomic weight of He= 4, moles of Helium= 10*10-6/4 =2.5*10-6 moles

1 mole of any substance contains 6.023*1023 molecules

2.5*10-6 moles contains 2.5*6.023*1017 molecules=15.1*1017 molecules

1pico second =10-12 seconds

4587 molecules escape in 10-12 seconds

15.1*1017 molecules escape 15.1*1017*10-12/4587=329 seconds

3.154*107 seconds are there in 1 year

329 second are there in 1*329/(3.154*107)=1.04*10-5 years

Explanation / Answer

oles of 7.800 a Determine the partial pressure of the at ssoc argon gas in (11 poins) b. 440.0 g of xenon to the tank Determine the new total p presbure in the tank c. Determine the volume of the gas container d. Helium gas leaks from the container at the rate of 4587 molecules per picosecond. How mat years will it take to lose 10.0 g of helium from the tank?

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.