Aballoon containing Xe is filled with the same number of atoms satoment is true

Question

Aballoon containing Xe is filled with the same number of atoms satoment is true for these balloons at the same emperature and pressure? as another balloon containing He. Which (A) The hillooms have the same volume (8) The halloons have the same mass of gas The balloons contain gases with the same density (D) The balloons contain atoms with the same average speod 56. A 1500 mL balloon is filled with He gas at 25 °C with an atmospheric pressure of 1.04 atm. How many moles of He are in the balloon? (B) 23 mol (D) 0.064 mol (A) 16 mol 0.76 mol 57. Which of theA gases in the graph has the largest molar mass? (All of the gases are at the 500 1000 1500 2000 molecular speed (m/sec) (A) A (B)B(CC(D) D which gas will have the highest rate ofeffusion? (A) 04g) (B) H0g) (C) CO(g) (D) Artg) 59 Which statement is true for this oxidation-reduction reaction? ZFe_ + 212Fe" +12 (A) tion is reduced and its oxidation number increase (B) I-ion is reduced and its oxidation number decreases. (C) I ion is oxidized and its oxidation number increase (D) I ion is oxidized and its oxidation number decreases. What is the oxidation number of manganese, Mn, in 60. 61. 100J of energy as heat is transferred to equal mass samples of four metals at the same initial temperature Which metal reaches the highest temperature? (The specific heat of each metal is given in parentheses in units of Jgl c') (A) iron (0450) (B) gold (0.129) (D) aluminum (0.902) (C) copper (0.385)

Explanation / Answer

61.

Answer is option (B) gold (0.129)

Since, gold has the lowest specific heat.

Specific heat is J g-1 K-1.
A high value of specific heat means that it takes MORE energy to raise (or lower) its temperature. A low value means that it does not take very much energy to heat or cool it.

Adding heat to a “low specific heat” compound will increase its temperature much more quickly than adding heat to a high specific heat compound.

60.

Ca(MnO4)2

Let the oxidation number of Mn be x

So,

+2 + 2 [ x + 4 ( -2) ] = 0
or, 2 + 2( x – 8) = 0
or, 2( x – 8) = -2
or, ( x – 8) = -1
or, x = -1 + 8 = 7

Answer is option (D) + 7.

59.

Answer is option (C) I- ion is oxidized and its oxidation number increase.

Since 2I- is converted to I2, so electron is given out, which means an oxidation.

So, I at oxidation number -1 has gone to 0.

So oxidation number increased.

56.

We know that

PV = nRT
n = PV / RT

Volume, V = 1500 mL = 1.5 L
Temperature, T = 25 oC = 298 K
Pressure, P = 1.04 atm
R = gas constant = 0.082 L atm mol-1 K-1

So, n = [ (1.04 atm) (1.5 L)] / [ (0.082 L atm mol-1 K-1) (298 K) ]
         = 0.064 mol

Answer is option (D) 0.064 mol

57.

Root mean square velocity, rms = (3RT/M)½

The speed of the molecules in a gas is proportional to the temperature and is inversely proportional to molar mass of the gas. So, higher the molar mass, less is the speed.

So, answer is option (A) A

58.

Graham's Law states that the rate of effusion of two different gases at the same conditions are inversely proportional to the square roots of their molar masses.

So, lower the molar mass less higher will be the rate of effusion.

So, H2O(g) has the lowest molar mass of 18 g/mol

So, answer is option (B) H2O(g)

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