Aball of mass \"m\", which is moving with a speed \"v1\" inx-direction, strikes

Question

Aball of mass "m", which is moving with a speed "v1"

inx-direction, strikes another ball of mass "2m", placed at the

origin of horizontal planar coordinate system. The lighter ball

comes to rest after the collision, whereas the heavier ball

breaks in two equal parts. One part moves along y-axis with a

speed "v2". Find the direction of the motion of other part.

[Answer: =tan1(v2/v1) below horizontal]

Explanation / Answer

Acccording to conservation of momentum we have             P i = Pf mv1+ 0 = 0 +mv2cos90 +mv2cos     ( along thehorizontal direction)    ==> v1 = v2cos    .............1 Along the vertical direction we have             0 = mv2sin90 - mv2sin       ==> v2 = v2/ sin       ............2 From 1 and 2 we get               v1 = (v2 / sin )cos       ==> cot = v1 /v2       ==> tan = v2 /v1       ==> =tan-1 (v2 / v1)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.