I’m so lost and I need a further explanation for problems 1, 7+8, and 18+19. I’m

Question

I’m so lost and I need a further explanation for problems 1, 7+8, and 18+19. I’m not sure how my teacher got his answers and I want to compare my answer with yours. Please show me your steps so I can chat with you and understand. Please remember Chegg's 5 subsets per question policy, which means that you must go over 1, 7+8, and 18+19 in order for it to be considered as a complete answer. I have a final exam TODAY and I can’t ask anyone else

1. An open end mercury manometer was constructed from a U-shaped tube. In a particular measurement, the level in the end connected to the gas manifold, on which the experiment was being conducted, measured 76.2 cm above the U-neck, while the level in the open end (to the atmosphere) was 23.8 cm above the U-neck. The outside air pressure in the laboratory was measured as 754 torr. What is the pressure in the gas manifold? A) 230 torr B) 236 torr C) 241 torr D) 246 torr E) 1278 torr

Explanation / Answer

(1)

manometers can be read directly. The difference in the fluid height = difference in pressure between the tank and the atmosphere.

since the level in the arm connected to the tank was higher than the arm connected to atmosphere, therefore atmospheric pressure is higher by 76.2cm - 23.8cm = 52.4cm = 524mm of the fluid in the manometer. which happens to be mercury. ie.. ?P = 524mmHg = 524torr

So...
atmospheric pressure - tank pressure = 524 torr
754torr - tank pressure = 524 torr
tank pressure = 230 torr

Therefore, option (a) is correct.

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