Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

D) the wavelength 16. According to the Balmer-Rydberg equation, electromagnetic

ID: 698432 • Letter: D

Question

D) the wavelength 16. According to the Balmer-Rydberg equation, electromagnetic radiation will be absorbed when an electron undergoes which of the following transitions with wavelength A-486.1 nm 17. Fo r hydrogen, what is the wavelength of the photon emitted when an electron drops from a 3d orbital to a 2p orbital in a hydrogen atom? The Rydberg constant is 1,097 102 nm1, A) 656.3 nm B) 486.2 nm C) 364.6 nm D) 2.057 10-3 nm 18. According to the Bohr model, when a hydrogen electron makes a transition from ne4 to n-2, which of the following statements is true? I Energy is emitted II. Energy is absorbed. III. Electrons lose energy. IV. Electrons gain energy A) I only B) I and III c) I and IV D) II and IV 19. An old copper penny has a mass 3 × 1022 times that of a copper atom. Compare the de Broglie wavelength of a penny moving at 0.5 m/s to that of a copper atom moving 104 times as fast. The wavelength for the A) copper atom is 3 1018 times that of the penny. B) copper atom is 3 1026 times that of the penny C) penny is 3 x 1018 times that of the copper atom. D) penny is 3 1026 times that of the copper atom. 20. How many subshells are there in the shell with n-6? A) 5 B) 6 C) 15 D) 36 21. How many orbitals are there in the seventh shell? A) 6 B)7 C) 21 D) 49 22. For a multielectron atom, a 3s orbital lies lower in energy than a 3p orbital because A) a 3p orbital has more nodal surfaces than a 3s orbital. B) other electrons more effectively shield electrons in the 3s orbital from the nucleus. C) other electrons more effectively shield electrons in the 3p orbital from the nucleus.

Explanation / Answer

16) Option B. Tranition from m=2 to n=4

17) From Rydberg equation:

       1/lambda = ZR2[1/nf2 - 1/ni2] = 1 * 1.097 x 10-2 nm-1 [ 1/4 - 1/9] = 1.097 x 10-2 nm-1 [0.25-0.11] = 0.0015358 nm-1

Lambda = 651.12 nm

18) When a hydrogen electron makes transition from n=4 to n=2 energy is emitted in the form of light and electron loses energy.

option B is the right answer.

**note: Not able to answer all the question due to policy guidelines and time constraints