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l The correct answer for the following calculation is (01002843)012 80184). = 0.

ID: 698176 • Letter: L

Question

l The correct answer for the following calculation is (01002843)012 80184). = 0.00032 a) 110 b) 113.736 c) 113.74 d) 113.7e 113.73635 2. In which pair do both compounds exhibit ionic bonding? a) PCIs and HF c) RbCl and CaO Na2SOs and BH b) d) KI and O 3. In which choice below are the elements ranked in order of increasing electr a) P, CI, S, Al, Ar, Si b) Ar, Cl, S, P, Si, A c) Al, Si, P, S, Cl, Ar d) Al, Si, S, P, Cl, Ar An electron in a hydrogen atom is found to have an energy of-1.362 What orbit would the electron be in according to the Bohr model of (Ru=2.18x10-18 J ) 4. c) 4 d) 3 a) b) 2

Explanation / Answer

1. (0.002843)(12.80184)/0.00032 = 0.03639563112/0.00032
                                = 113.74
c) 113.74
2.The ionic bond formed between metal and non metal.
c. RbCl and CaO
3.In a period electronegativity increases from left to right
c) Al, Si,P,S,Cl,Ar
4. En = -RH/n^2
-1.362*10^-18 = -2.18*10^-18/n^2
n^2     = -2.18*10^-18/-1.362*10^-19
n^2    = 16
n     = 4
c) 4