l T-Mobile 7:32 PM blackboard.kean.edu Suppose you have a 100 turn solenoid and
ID: 2029801 • Letter: L
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l T-Mobile 7:32 PM blackboard.kean.edu Suppose you have a 100 turn solenoid and pull it out quickly. The solenoid is 12 cm on a side and has a resistance of 75 ohms and is being pulled out of a 5 T magnetic field in 025 seconds. What is the induced emf? Osav A rectangular loop of wire with a size of 10x20 cm is placed in a uniform magnetic field of 2 T. Find the magnetic flux through the loop when the angle between the field and the normal to the loop is 60° QUESTION coil of wire with 10 turns and an area of 0.5m2 is A square placed in a parallel uniform magnetic field of 0.75 T. The coil is turned so it is now perpendicular to the magnetic field. This action takes 0.15 s to complete. What is the emf induced in the coil? QUESTIONExplanation / Answer
magnetic flux = N*B*A*costheta
theta = 0
induced emf = -rate of change in flux
emf = -N*A*(dB/dt)
emf = -N*A*(B2-B1)/t
B2 = 0
B1 = 5 T
A = area of coil = l^2
N = number of turns
induced emf = 100*0.12^2*5/0.25 = 29 V <<<----ANSWER
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magnetic flux = N*B*A*costheta
A = area of coil = l*b = 0.1*0.2 m^2
N = number of turns = 1
theta = 60
magnetic field B = 2 T
magnetic flux = 1*2*0.1*0.2*cos60 = 0.02 wb <<<-------ANSWER
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magnetic flux = N*B*A*costheta
induced emf = -rate of change in flux
emf = -N*A*B(d/dt)costheta
emf = -N*A*B(costheta2-costheta1)/t
B = 0.75 T
A = area of coil = 0.5
N = number of turns = 10
theta 1 = 0
theta2 = 90
induced emf = -10*0.5*0.75*(cos90-cos0)/0.15 = 25 V <<<----ANSWER
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