the heat of combustion of propane C3H8, 2220 kj/mol the specific heat of copper

Question

the heat of combustion of propane C3H8, 2220 kj/mol the specific heat of copper is .385j/g C how many grams of propane must be burned to raise the temperature of a 5.0kg block of copper. from 15.0 C to 55C assuming. nonof the heat is lose of the surrounding. ___________ g

The heat of combustion of propane, C3Hg, 2220 kJ/mol. The specific heat of copper is 0.38s I/g C specific heat of copper is 0.385 J/g·°C. How many grams of propane must be burned to raise the temperature of a 5.0 kg block of copper from 15.0°C to SSOC, assuming none of the heat is lost to the surroundings

Explanation / Answer

heat given by propane = heat absorb by Cu

first calculate the amount of Heat by Cu, Q= mcdT

m = mass of Cu, 5.0 kg or 5000 g

c specific heat ; 0.385 J/ g-C

dt temperature change = 55 C-15 C = 40 C

therefore ; Q = 5000 * 0.385 * 40

= 77000 J

= 77 KJ

Now calculate the mole of propane as follows: total amount of heat / heat of combustion of propane

= 77 / 2220 KJ/mol

= 0.03468 moles propane

Amount of propane = number of moles * molar mass

= 0.03468 moles propane * 44.09562 g/mol

= 1.53 g propane  

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