ELECTROCHEMISTRY -Analyzing a galvanic cell A galvanic cell is powered by the fo

Question

ELECTROCHEMISTRY -Analyzing a galvanic cell A galvanic cell is powered by the following redox reaction: 2 103 (aq) + 12H+(aq) + 10 Br_ (aq)-12(s) + 6H20() + 5 Br2(,) Answer the following questions about this cell. If you need any electrochemical data, be sure you ge Write a balanced equation for the half-reaction that takes place at the cathode. Write a balanced equation for the half-reaction that takes place at the anode. Calculate the cell voltage under standard conditions. Round your answer to 2 decimal places.

Explanation / Answer

cathode half reaction
2IO3^- (aq) + 6H^+ (aq) + 10e^- --------> I2 (aq) + 3H2O(l)     E0 = 1.195v
anode half reaction
10Br^- (aq) -----------> 5Br2(l)                                 E0 = -1.07v

2IO3^- (aq) + 6H^+ (aq) + 10e^- --------> I2 (aq) + 3H2O(l)             E0 = 1.195v

10Br^- (aq) -----------> 5Br2(l)                                        E0 = -1.07v
-------------------------------------------------------------------------------
2IO3^- (aq) + 10Br^- (aq) + 6H^+ (aq) ---------> 5Br2(l) + I2(aq) + 3H2O E0cell = 0.125v

E0cell = 0.125V >>>>answer

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