ELECTROCHEMIS 122L CHEMISTRY 2. Complete the following table for the indicated h

Question

ELECTROCHEMIS 122L CHEMISTRY 2. Complete the following table for the indicated half-cell combinations at standard conditions: Toward What would WhichWhichwhich metal the potential Couples metal is the metal is thedo the be under anode? flow?conditions? Cu/Cu*, Ag/Ag Zn/Zn", Mg/Mg Pb/Pb+, Ni/Ni 3. Compare the potentials you measured between the Zn/Zn+ and Cu/Cu" half-cells before and after adding excess NH to thu/u half-cell. Did the potential 4. Compare the potentials you measured between the Ag/Agt and Cu/Cu" half-cells before and afer adding excess NH to the Cu/Cu half-cell. Did the potential increase or decrease? Explain the result in rerms of the Nernst .equation

Explanation / Answer

2)

Cu= + 0.34v

Ag = +0.80v

Zn= - 0.76 v

Mg= -2.38 v

Eocell = EoZn - EoMg

= -0.76 -(- 2.38) = 1.62v

Pb= -0.13 v

Ni =-0.26v

Eocell = EoPb - EoNi

= -0.13 - (- 0.26) =0.13v

Zn = -0.76 v

Ag = + 0.80v

Eocell = EoAg -EoZn

= 0.80 - (- 0.76) = 1.56v

Couples Reduction potential Anode Cathode electron flow Eocell(cell potential) Cu/Cu2+, Ag/Ag+

Cu= + 0.34v

Ag = +0.80v

Cu Ag Ag Eocell = EoAg -Eocu = 0.80 - 0.34 = 0.54v Zn/Zn2+Mg/Mg2+

Zn= - 0.76 v

Mg= -2.38 v

Mg Zn Zn

Eocell = EoZn - EoMg

= -0.76 -(- 2.38) = 1.62v

Pb/Pb2+, Ni/Ni2+

Pb= -0.13 v

Ni =-0.26v

Ni Pb Pb

Eocell = EoPb - EoNi

= -0.13 - (- 0.26) =0.13v

Zn/Zn2+,Ag/Ag+

Zn = -0.76 v

Ag = + 0.80v

Zn Ag Ag

Eocell = EoAg -EoZn

= 0.80 - (- 0.76) = 1.56v

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