question 8 and 9 please, I know the answers , but how do we get there, and can y
ID: 695487 • Letter: Q
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question 8 and 9 please, I know the answers
, but how do we get there, and can you go through everything in detail because I don't know how to do this
from the nucleus of the same atom energy is absorbed. (B) energy is liberated. (C) there is no energy change. (D) the atom must assume a different ionic charge (E) light of a definite wave length is emitted. 8. Calculate the frequency of a photon absorbed when the hydrogen atom undergoes a transitiorn from n = 2 to n = 4 (9-1.0968 x 107 m.') 2.056 x 10"Hz 6169 x 1014 6621%2 xls", 2.742 x 10° Hz 8.226 x 1014 A) (B) (D) An electron in the n = 6 level emits a photon with a wavelength of 410.2 nm. To what energy level does the electron move? (H-1 .0968 x 107 m -1) -ooy 1 y rlo-13 (A) n- 1 (B) n=2 (C) n-3 (D) n=4 The energy ofthe electron in the most stable orbital of the hydrogen atom is-2.18 x 10-1 The energy of the electron after promotion to the next highest orbital is (in J): 10. (A) 0 (B)) -5.44 x 10"9 (C) -2. I 8 x 10-18 (D) 1.55 x 10'18 (E) -4.36 x 10'18Explanation / Answer
8)
Here photon will be captured and it will excite the atom
1/wavelength = -R* (1/nf^2 - 1/ni^2)
R is Rydberg constant. R = 1.0968*10^7
1/wavelength = - R* (1/nf^2 - 1/ni^2)
1/wavelength = - 1.0968*10^7* (1/4^2 - 1/2^2)
wavelength = 4.893*10^-7 m
we have:
wavelength = 4.893*10^-7 m
we have below equation to be used:
frequency = speed of light/wavelength
=(2.998*10^8 m/s)/(4.893*10^-7 m)
= 6.169*10^14 Hz
Answer: C
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