13. According to the following cell notation, which species is undergoing oxidat

Question

13. According to the following cell notation, which species is undergoing oxidation? Zn | Zn (aq) 11 Mn2 (aq)I Mno(s) | Pt(s) a. Mn2 (aq) b. Zn2(ag) c. Mno2(s d. Zn(s) e. Pt(s) 14. What is the cell reaction for the following electrochemical cell? a. 3Zn(s) + 2Sc3.(aq)-> 2Sc(s) + 32n"(aq) c. Zn(s) + Zn2+(aq) Sc(s) + se.(aq) d. Zn(s) + Se*(aq) Sc(s) + Zn2"(aq) e, Sc(s) + Zn2'(aq) Zn(s) + ScHaq) 15. What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions? Cu2+(aq) + 2e- Cu(s) E' = 0.337 V 24 a. Cu".(aq) + Pb(s) Cu(s) + Pb?"(aq); 0.467 V b. Cu(s) + Pb?"(aq) Cu2+(aq) + Pb(s);-0.467 V C. Cu"(aq) + Pb?"(aq) Cu(s) + Pb(s); 0.207 V d. Cur(aq) + Pb(s) Cu(s) + Pb?"(aq); 0.234 V e. Cu(s) + Pb?"(aq) Cu""(aq) + Pb(s);-0.234 V

Explanation / Answer

13)

Zn is changing from Zn to Zn2+

So, oxidation number of Zn is increasing

So, Zn is undergoing oxidation

Answer: d

14)

oxidation half cell is:

Zn(s) —> Zn2+(aq)   + 2e-

reduction half cell is:

Sc3+(aq)   + 3e- —> Sc(s)

to balance electron multiply 1st equation by 3 and end equation by 2 and then add them

the net reaction is:

3 Zn(s) + 2 Sc3+(aq) —> 2 Sc(s) + 3 Zn2+ (aq)

Answer: a

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