PCl5 <---> PCl3 + Cl2 Phosphorus pentachloride is injected into a container unti
ID: 694034 • Letter: P
Question
PCl5 <---> PCl3 + Cl2Phosphorus pentachloride is injected into a container until the initial pressure is 0.82atm. At equilibrium, the total pressure in the container is 1.2atm. Determine the partial pressure of each gas at equilibrium and calculate value of Kp PCl5 <---> PCl3 + Cl2
Phosphorus pentachloride is injected into a container until the initial pressure is 0.82atm. At equilibrium, the total pressure in the container is 1.2atm. Determine the partial pressure of each gas at equilibrium and calculate value of Kp
Phosphorus pentachloride is injected into a container until the initial pressure is 0.82atm. At equilibrium, the total pressure in the container is 1.2atm. Determine the partial pressure of each gas at equilibrium and calculate value of Kp
Explanation / Answer
the reaction is PCl5(g)---->PCl3(g)+Cl2(g)
initial pressure of PCl5= 0.82 atm, let x= drop in pressure of PCl5 to reach equilibrium
at equilibrium, PPCl5= 0.82-x, PPCl3= x and PCl2=x
where P represents the partial pressure
total pressure at equilibrium= sum of partial pressures = 0.82-x+x+x=1.2
x= 1.2-0.82= 0.38 atm
at Equilibrium, PPCl5= 0.82-0.38= 0.44 atm, PPCl3= PCl2=0.38 atm
Kp for the reaction = PCl2*PPCl3/PPCl5= 0.38*0.38/0.44= 0.33
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