a) If the student started with 10.6 g of benzaldehyde and 29 g of acetone, what

Question

a) If the student started with 10.6 g of benzaldehyde and 29 g of acetone, what is the theoretical yield of the product? b) If 10.5 g of the yellow product is obtained, calculate the percent yield c) What would be the expected product for a 1:1 mole ratio of the reactants? d) Another student carries out this reaction using 8 moles of benzaldehyde and 5 moles of acetone and obtains 3 moles of dibenzalacetone. i) What is the limiting reactant? ii) What is the excess reactant and how many moles of this reactant will be left at the end of the reaction? iii) What is the percent yield of this reaction? iv) What is the actual grams of the yellow product obtained in this reaction?

Explanation / Answer

a) moles benzaldehyde = 10.6 g/106.124 g/mol = 0.1 mol

moles acetone = 2.9 g/58.08 g/mol = 0.05 mol

theoretical yield of product = 0.05 mol x 234.29 g/mol = 11.7145 g

b) actual yield of product = 10.5 g

Percent yield = 10.5 g x 100/11.7145 g = 89.63%

c) expected product if 1:1 mole ratio of benzaldehyde and acetone is used would be benzalacetone. A single aldol reaction would occur.

d) 8 mol of benzaldehyde reacted with 5 mol of acetone to give 3 mol of product

i) limiting reactant = benzaldehyde

8 mol benzaldehyde would react with 4 mol of acetone leaving behind 1 mol of acetone

ii) excess reactant = acetone

moles of excess reactant remained after completion of reaction = 1 mol acetone

iii) percent yield = 3 mol x 100/4 mol = 75%

iv) actual yield of product = 3 mol x 234.29 g/mol = 702.87 g

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