0 12/5/2017 1 1 :55 PM 87.5/100 O 1 1/29/2017 05:38 PM PrintCalculatorPeriodic T

Question

0 12/5/2017 1 1 :55 PM 87.5/100 O 1 1/29/2017 05:38 PM PrintCalculatorPeriodic Table Gradebook Question 8 of 22 Map Sapling Learning macmillan learning Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol (AG-2870 kJ/mol). If one contraction cycle in muscle requires 67 kJ, and the energy from the combustion of glucose is converted with an efficiency of 45% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? Round your answer to the nearest whole number Number cycles per mole glucose Hint Previous Give Up & View Solution O check Answer 0 Next a Exit

Explanation / Answer

total energy avaialable = - 2870 kJ/mol

energy utilised for contraction = 2870 x 45 /100

                                                = 1291.5 kJ

one contraction cycle in muscle requires 67 kJ.

No of contraction takes place = 1291.5 / 67

                                                = 19.3

number of contration cycles = 19

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