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1) For the chemical reaction, 2CH 4(g) <-->C 2 H 2(g) + 3H 2(g) , K= 0.165 at175

ID: 691246 • Letter: 1

Question

1) For the chemical reaction, 2CH4(g) <-->C2H2(g) + 3H2(g) , K= 0.165 at1752o C. What is Kp for the reaction at thistemperature? 2) For the reaction, N2(g) + 3H2(g)<--> 2NH3(g) , Kp = 4.95 x10-3 at 270oC. What is K for the reaction atthis temperature? 1) For the chemical reaction, 2CH4(g) <-->C2H2(g) + 3H2(g) , K= 0.165 at1752o C. What is Kp for the reaction at thistemperature? 2) For the reaction, N2(g) + 3H2(g)<--> 2NH3(g) , Kp = 4.95 x10-3 at 270oC. What is K for the reaction atthis temperature?

Explanation / Answer

1) For the chemical reaction, 2CH4(g) <-->C2H2(g) + 3H2(g) , K= 0.165 at1752o C. What is Kp for the reaction at thistemperature? We know that Kp = Kc * (RT) n Where T = Temperature = 1752 o = 1752 + 273 = 2025K R = gas constant = 0.0821 L atm / mol - K n = No . of moles of gaseous products - No . of moles ofgaseous reactants      = (1+3) - 2      = 2 Plug the values we get Kp = 0.165 * ( 0.0821 * 2025 )2                                         = 4.5605*10 3 2) For the reaction, N2(g) + 3H2(g)<--> 2NH3(g) , Kp = 4.95 x10-3 at 270oC. What is K for the reaction atthis temperature? We know that Kp = Kc * (RT) n Where T = Temperature = 270 o C = 270 + 273 =543K R = gas constant = 0.0821 L atm / mol - K n = No . of moles of gaseous products - No . of moles ofgaseous reactants      = 2 - ( 1+3)      =-2 Plug the values we get K = Kp *  (RT)-n                                       = 4.95 x 10-3 * ( 0.0821 *543 ) 2                                         = 9.837 We know that Kp = Kc * (RT) n Where T = Temperature = 270 o C = 270 + 273 =543K R = gas constant = 0.0821 L atm / mol - K n = No . of moles of gaseous products - No . of moles ofgaseous reactants      = 2 - ( 1+3)      =-2 Plug the values we get K = Kp *  (RT)-n                                       = 4.95 x 10-3 * ( 0.0821 *543 ) 2                                         = 9.837