1) For NaOH ... a) If 39.99 g NaOH in 1L of water is a 1 M solution, what would
ID: 12164 • Letter: 1
Question
1) For NaOH...
a) If 39.99 g NaOH in 1L of water is a 1 M solution, what would the molarity be if 39.99 g NaOH was dissolved in 0.5 L of water?
b)How many grams of NaOH would you need to make a 0.5 M solution? (Hint: Half of the mass of NaOH in 1L water) . Why?
c) If we can obtain the MW of NaOH by adding the molecular masses of each element in the compound (mass of Na + mass of O + mass of H), then what is the MW of sodium chloride, NaCl? Why?
Please show all calculations step by step and please be as detailed in each step as is possible. Please do not skip any steps. Thank You
Explanation / Answer
a) 39.9 is the mass of NaOH. It is also the molecular weight so it is equal to 1 mole. Molarity is Moles/Liter thus 1moles NaOH/ 1 Liter= 1 Molar 1 moles/.5 L = 2 M b) 1 mole NaOH = 39.99 grams NaOH .5 moles NaOH/1 L= .5 M c) You just add the individual molecular weights of each element Na =22.98 Cl= 35.453 22.98 + 35.453 = 58.433
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