1. The problem statement,all variables and given/known data The specific gravity
ID: 690400 • Letter: 1
Question
1. The problem statement,all variables and given/known dataThe specific gravity of nitrobenzene is 1.20.
a) Calculate the mass in kg of 250 litres of nitrobenzene.
b) Calculate the volumetric flow in mL/min corresponding to a massflow of 30 lbm/h of nitrobenzene.
c) Calculate the density of a mixture composed of 20 litres ofnitrobenzene and 3 ft^3 of benzene (SG = 0.879), by supposing thatthe volume of the mixture is the sum of the volume of the twosubstances.
2. Relevant equations
SG=p/pref
v=m/p
3. The attempt at a solution
a) I got 1.2*250=300 kg
b) I got v= 183.33 ml/min
C) I do not know how to solve it
I find 3ft^3= 84.950
and I do not how to solve it?Please help me 1. The problem statement,all variables and given/known data
The specific gravity of nitrobenzene is 1.20.
a) Calculate the mass in kg of 250 litres of nitrobenzene.
b) Calculate the volumetric flow in mL/min corresponding to a massflow of 30 lbm/h of nitrobenzene.
c) Calculate the density of a mixture composed of 20 litres ofnitrobenzene and 3 ft^3 of benzene (SG = 0.879), by supposing thatthe volume of the mixture is the sum of the volume of the twosubstances.
2. Relevant equations
SG=p/pref
v=m/p
3. The attempt at a solution
a) I got 1.2*250=300 kg
b) I got v= 183.33 ml/min
C) I do not know how to solve it
I find 3ft^3= 84.950
and I do not how to solve it?Please help me
Explanation / Answer
The specific gravity of nitrobenzene is 1.20.a) Calculate the mass in kg of 250 litres of nitrobenzene.
We know that density , d = mass m / Volume V So , m = d * v =1.2 g / mL * 250 L =1.2 g / mL * 250 * 1000 mL =300000 g =300 Kg
b) Calculate the volumetric flow in mL/min corresponding to a massflow of 30 lbm/h of nitrobenzene. mass flow of 30 lbm/h of nitrobenzene 1n 1 hour the mass flow is 30 lb = 30 * 453.6g Since 1 lb = 453.6 g In 60 min the mass flow is 30* 453.6 g In 1 min the flow will be ( 30 * 453.6 ) / 60 = 226.8 g = 226.8 g / 1.2 g /mL ( since Volume = mass / density ) = 189 mL
c) Calculate the density of a mixture composed of 20 litres ofnitrobenzene and 3 ft^3 of benzene (SG = 0.879), by supposing thatthe volume of the mixture is the sum of the volume of the twosubstances. mass of 20 L nitrobenzene , m' = density * Volume = 1.2 g / mL * 20 * 10^3 mL = 24 * 10^3 g = 24 Kg 1 ft^3 = 28.32 L 3 ft^3 = 3 * 28.32 L = 84.96 L So , mass of 84.96L benzene , m'' = density * Volume = 0.879 g / mL * 84.96 * 10^3 mL = 74.679 * 10^3g =74.679Kg Total Volume V = 20 + 84.96 L = 104.96 L Total mass , m = m' + m" = 98.679 Kg Density of the mixture , D = m / V = 0.9401 Kg / L
= 0.879 g / mL * 84.96 * 10^3 mL = 74.679 * 10^3g =74.679Kg Total Volume V = 20 + 84.96 L = 104.96 L Total mass , m = m' + m" = 98.679 Kg Density of the mixture , D = m / V = 0.9401 Kg / L
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