The enthalpy of vaporization of ethanol is 43.3 kJ/mol and theenthalpy of fusion

Question

The enthalpy of vaporization of ethanol is 43.3 kJ/mol and theenthalpy of fusion of ethanol is 5.01 kJ/mol. How much heat isreleased when 2.35 mol of ethanol vapor is deposited as asolid?
Answer: 114 kJ
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What I did was multiply 2.35 mol by (43.3 - 5.01 kJ)/mol,which gave me 89.9 kJ. If anyone can point out what I did wrong,I'd really appreciate it. Thanks!
Answer: 114 kJ
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What I did was multiply 2.35 mol by (43.3 - 5.01 kJ)/mol,which gave me 89.9 kJ. If anyone can point out what I did wrong,I'd really appreciate it. Thanks!

Explanation / Answer

The problem your having is quite simple you should add theenthalpies together then multiply them by the number of moles and bingo you will get the correct answer the enthalpies are added because the vaporized then fused toform the solid

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