Suppose you mix 24.0 mL of 0.234 M FeCl 3 solution with 45.1 mL of 0.453 M NaOH.

Question

Suppose you mix 24.0 mL of 0.234M FeCl3 solution with 45.1 mL of 0.453 M NaOH.
What is the concentration of the excess reactant remaining insolution after the maximum mass of Fe(OH)3 hasprecipitated?

I found the maximum mass of Fe(OH)3 that will be to be .600grams.
And the excess reactant is NaOH

I know Molarity= moles of solute/ Liters of solute
I just don't know if I should use the 45.1 mL (.0451 L) or if Ishould use the moles that theoretically should be yielded giventhat much Fe(OH)3 or how much is used when you use all of thelimiting reactant or if I have to subtract two amounts..

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