what mass of solid Aluminum hydroxide (Al(OH) 3 ) can bemade from the reaction o

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Explanation / Answer

Step 1) Write the balanced chemical equation:Al(NO3)3 + 3KOH -->Al(OH)3+3KNO3 Step 2) Find the moles of reactants: Multiply the number of mL by1/1000 to convert to Liters, then by the Molarity given above tofind the moles. You should get 0.0375 moles ofAl(NO3)3 and 0.05 moles of KOH. Step 3) Determine which reactant is the limiting reactant. Todo this, divide .05 by 3, and compare that to the moles ofAl(NO3)3. Because the moles of KOH/3 issmaller, that is your limiting reactant (you divide by 3 becauseyou divide the moles of each reactant by it's coeffiecent) Step 4) Convert moles of KOH to moles of Al(OH)3. In reality, you've already done this, because for every 3 moles ofKOH, there is 1 mole of Al(OH)3 (again usingcoeffeicints from the balanced equation). Therefore, you have0.017 moles. Step 5) Convert to grams using molar mass. You can eithercalculate this yourself, or use a molar mass calculator. Then, when you have it, just multiply moles by the molarmass. And that is your answer.

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