what maximum current is delivered by an AC source with .max-57.7 V and f= 81.9 H

Question

what maximum current is delivered by an AC source with .max-57.7 V and f= 81.9 Hz when connected across a 3.70-uF capacitor? Step 1 The applied AC source determines the voltage amplitude and frequency. We will compute the reactance of the capacitor at this frequency and use the definition of reactance to find the current. The impeding effect of capacitance C in an AC circuit with frequency fis called capacitive reactance. Capacitive reactance is defined by the following equation 27IfC For the maximum current Imax at applied voltage max, we have Xc Substituting the expression for capacitive reactance and solving for the current gives Avrmax = . (2/T) C max Xc Hz x10-6 F mA

Explanation / Answer

given voltage applied=V=57.7 volts

frequency=f=81.9 Hz

capacitance=C=3.7 uF

then capacitive impedance=Xc=1/(2*pi*f*C)=525.21 ohms

then maximum current=maximum voltage/impedance magnitude

=57.7/525.21

=0.10986 A

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