help please step by step... A.an aqueous solution of _____ is added to a mixture
ID: 689729 • Letter: H
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help please step by step... A.an aqueous solution of _____ is added to a mixture ofF- and SO4 ^2- the fluoride ion will precipotate but thesulfate ion will remain in solution 1. AgNO3 2.Pb(CIO4)2 3. HNO3 4. AlCl3 5LiBr B. if 6.46 L of gasepus ethanot reacts with 32.1 Lo2. what is the maximum volume of gaseous water produced ? theT and P of the reactants and products is 425 c and 1.0atm CH3CH2OH(g) + 3O2 (g) ------> 2 CO2 (g) + 3 H2O (g) C. A 2.0 g sample of FeF2 x H2O is dried in an oven.when the anhydrous salt is removed from the oven. its mass is .789g . what the the value of x??? help please step by step... A.an aqueous solution of _____ is added to a mixture ofF- and SO4 ^2- the fluoride ion will precipotate but thesulfate ion will remain in solution 1. AgNO3 2.Pb(CIO4)2 3. HNO3 4. AlCl3 5LiBr B. if 6.46 L of gasepus ethanot reacts with 32.1 Lo2. what is the maximum volume of gaseous water produced ? theT and P of the reactants and products is 425 c and 1.0atm CH3CH2OH(g) + 3O2 (g) ------> 2 CO2 (g) + 3 H2O (g) C. A 2.0 g sample of FeF2 x H2O is dried in an oven.when the anhydrous salt is removed from the oven. its mass is .789g . what the the value of x???Explanation / Answer
A.an aqueous solution of LiBr is added to amixture of F- and SO4 ^2- the fluoride ion will precipotatebut the sulfate ion will remain in solution B. if 6.46 L of gasepus ethanot reacts with 32.1 Lo2. what is the maximum volume of gaseous water produced ? theT and P of the reactants and products is 425 c and 1.0atm CH3CH2OH(g) + 3O2 (g) ------> 2 CO2 (g) + 3 H2O (g) 1 mole of ethanol reacts with 3 moles of O2 produces 3 moles of water No . of moles of ethanol , n e = PV / RT = ( 1 * 6.46 L ) / ( 0.0821L atm / mol - K * 425K ) =0.185 moles No . of moles of Oxygen , n o = PV / RT = ( 1 * 32.1L ) / ( 0.0821L atm / mol - K * 425K ) = 0.919 moles 1 mole of ethanol reacts with 3 moles of O2 0.185 mole of ethanol reacts with X moles ofO2 X = ( 3*0.185 ) / 1 = 0.555 moles of O2 So , 0.919 - 0.555 = 0.364 moles of O2 left unreacted 1 mole of ethanol produces 3 moles of water 0.185 moles of ethanol produces 3 * 0.185 moles = 0.555moles No . of moles of water , nw = PV / RT 0.555 = ( 1 * V ) / ( 0.0821L atm / mol - K * 425K) V = 19.36 L of water B. if 6.46 L of gasepus ethanot reacts with 32.1 Lo2. what is the maximum volume of gaseous water produced ? theT and P of the reactants and products is 425 c and 1.0atm CH3CH2OH(g) + 3O2 (g) ------> 2 CO2 (g) + 3 H2O (g) 1 mole of ethanol reacts with 3 moles of O2 produces 3 moles of water No . of moles of ethanol , n e = PV / RT = ( 1 * 6.46 L ) / ( 0.0821L atm / mol - K * 425K ) =0.185 moles No . of moles of Oxygen , n o = PV / RT = ( 1 * 32.1L ) / ( 0.0821L atm / mol - K * 425K ) = 0.919 moles 1 mole of ethanol reacts with 3 moles of O2 0.185 mole of ethanol reacts with X moles ofO2 X = ( 3*0.185 ) / 1 = 0.555 moles of O2 So , 0.919 - 0.555 = 0.364 moles of O2 left unreacted 1 mole of ethanol produces 3 moles of water 0.185 moles of ethanol produces 3 * 0.185 moles = 0.555moles No . of moles of water , nw = PV / RT 0.555 = ( 1 * V ) / ( 0.0821L atm / mol - K * 425K) V = 19.36 L of water No . of moles of Oxygen , n o = PV / RT = ( 1 * 32.1L ) / ( 0.0821L atm / mol - K * 425K ) = 0.919 moles 1 mole of ethanol reacts with 3 moles of O2 0.185 mole of ethanol reacts with X moles ofO2 X = ( 3*0.185 ) / 1 = 0.555 moles of O2 So , 0.919 - 0.555 = 0.364 moles of O2 left unreacted 1 mole of ethanol produces 3 moles of water 0.185 moles of ethanol produces 3 * 0.185 moles = 0.555moles No . of moles of water , nw = PV / RT 0.555 = ( 1 * V ) / ( 0.0821L atm / mol - K * 425K) V = 19.36 L of water C. A 2.0 g sample of FeF2 x H2O is dried in an oven.when the anhydrous salt is removed from the oven. its mass is .789g . what the the value of x? Mass of water = ( 2.0 - 0.789 ) = 1.211 g No . of moles of water , n = mass / Molar mass = 1.211 / 18 = 0.067 So , x = 0.067Related Questions
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