Spectroscopists study excited states is to gain informationabout the energies of

Question

Spectroscopists study excited states is to gain informationabout the energies of orbitals that are unoccupied in an atom'sground state. The following electron configuration represents anatom in an excited state. Identify the element, and give itscondensed ground-state configuration.

1s22s22p63s23p64s23d44p1



a. Cr: [Ar]4s3d5

b. Ga: [Ar]3d104s24p

c. Mn: [Ar]4s23d5

d. none of these

e. V: [Ar]4s23d3 Answer is C but can someone Pleaseexplain the problem well to me. Thanks! Spectroscopists study excited states is to gain informationabout the energies of orbitals that are unoccupied in an atom'sground state. The following electron configuration represents anatom in an excited state. Identify the element, and give itscondensed ground-state configuration.

1s22s22p63s23p64s23d44p1



a. Cr: [Ar]4s3d5

b. Ga: [Ar]3d104s24p

c. Mn: [Ar]4s23d5

d. none of these

e. V: [Ar]4s23d3 Answer is C but can someone Pleaseexplain the problem well to me. Thanks! Answer is C but can someone Pleaseexplain the problem well to me. Thanks!

Explanation / Answer

Since the outer orbital is 3d. When external energy is givento the system then the electron present in 3d orbital is goes tothe 4p orbital( which is of equal in energy of 3d (n+l) values). (n+l ) values : -------------- 3d --- ( 3 + 2 ) =5 4s --- ( 4 + 1 ) = 5 So , the original configuration is [Ar]4s23d5                              

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