1) a) Which of the solvents, ethylacetate (pKa = 21), tetrahydrofuran (pKa = 38)

Question

1) a) Which of the solvents, ethylacetate (pKa = 21), tetrahydrofuran (pKa = 38), or methanol (pKa =16), would be the best choice for a reaction involving the base((CH3)2CH)2NLi (Note:The pKa of((CH3)2CH)2NH is36)? b) Explain why you haveselected the solvent. In your explanation use both chemicalequations and words. 2) Whenlooking at the most stable conformations of substitutedcyclohexanes, groups larger than a hydrogen atom are usually in anequatorial position. Using both structures and words, explain whythis is lower energy situation. 1) a) Which of the solvents, ethylacetate (pKa = 21), tetrahydrofuran (pKa = 38), or methanol (pKa =16), would be the best choice for a reaction involving the base((CH3)2CH)2NLi (Note:The pKa of((CH3)2CH)2NH is36)? b) Explain why you haveselected the solvent. In your explanation use both chemicalequations and words. 2) Whenlooking at the most stable conformations of substitutedcyclohexanes, groups larger than a hydrogen atom are usually in anequatorial position. Using both structures and words, explain whythis is lower energy situation.

Explanation / Answer

a) tetahydrofuran b)because its pka is higher than the base involve in thereaction

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