A piece of stainless steel (specific heat = 0.50 Jg^-1c^-1) istransferred from a

Question

A piece of stainless steel (specific heat = 0.50 Jg^-1c^-1) istransferred from an oven at 191C^o into 125 mL of water at 23.6C^o.The water temperature rises to 50.5C^o . a)What is the mass of the steel? Express your answer using twosignificant figures. b)How precise is this method of massdetermination? Explain. can you write all steps please thank you A piece of stainless steel (specific heat = 0.50 Jg^-1c^-1) istransferred from an oven at 191C^o into 125 mL of water at 23.6C^o.The water temperature rises to 50.5C^o . a)What is the mass of the steel? Express your answer using twosignificant figures. a)What is the mass of the steel? Express your answer using twosignificant figures. b)How precise is this method of massdetermination? Explain. can you write all steps please thank you b)How precise is this method of massdetermination? Explain. can you write all steps please thank you

Explanation / Answer

Specific heat of steel C = 0.5 J / g oC Initial temp of steel t = 191 oC mass of water m = volume * density = 125 mL * 1 g / cm ^3 = 125 g Since 1 ml = 1 cm ^ 3 initial temp of water t ' = 23.6 oC Final temp T = 50.5 oC (a). we know heat loss by steel = heat gain by water                              M C dt = m c dt '             M * 0.5* ( 191-50.5 ) = 125 * 4.186 * ( 50.5-23.6 )                                            = 14075.425                                         M = 200.3 g                                         M = 200.3 g

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