[] d = / (l x C) = -0.296 degrees C = 9 mg / mL path length is 10 cm temp is 25

Question

[]d = / (l x C) = -0.296 degrees C = 9 mg / mL path length is 10 cm temp is 25 degrees C What is the specific rotation? My sample in the experiment weighed 0.39g (not sure if this isneeded) Thanks for your help! []d = / (l x C) = -0.296 degrees C = 9 mg / mL path length is 10 cm temp is 25 degrees C What is the specific rotation? My sample in the experiment weighed 0.39g (not sure if this isneeded) Thanks for your help! My sample in the experiment weighed 0.39g (not sure if this isneeded) Thanks for your help!

Explanation / Answer

We knw that Specific rortation[]d = / l*c From the given information , = -0.296 degrees C = 9 mg / mL path length is 10 cm = 1 dm Therefore specific rotaition,[]d   = 0.926 /1 * 9                                                     = - 0.102 degrees If the concentration of the sample weighed 0.39 gthen the specific rotaition   = -0.926 /1*39mg                                  = -0.0237 degrees C = 9 mg / mL path length is 10 cm = 1 dm Therefore specific rotaition,[]d   = 0.926 /1 * 9                                                     = - 0.102 degrees If the concentration of the sample weighed 0.39 gthen the specific rotaition   = -0.926 /1*39mg                                  = -0.0237 degrees

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