For combustion of hydrogenH 2 (g) + 1/2 O 2 (g) -> H 2 O(l) thereaction enthalpy

Question

For combustion of hydrogenH2(g) + 1/2 O2(g) -> H2O(l) thereaction enthalpy is -286 kJ/mol and the reaction Gibbs free energyis -237 kJ/mol. Calculate the maximum amount of electrical workthat may be generated by oxidizing 1 mole of hydrogen to water in afuel cell (find result in kJ Please show final answer For combustion of hydrogenH2(g) + 1/2 O2(g) -> H2O(l) thereaction enthalpy is -286 kJ/mol and the reaction Gibbs free energyis -237 kJ/mol. Calculate the maximum amount of electrical workthat may be generated by oxidizing 1 mole of hydrogen to water in afuel cell (find result in kJ Please show final answer

Explanation / Answer

We Know that :       The given Reaction is:
        H2(g) +1/2 O2(g) -> H2O(l)         G = H - PV        - G + H = work useful to draw electrical energy forthe formation of one mole of water        -286KJ - ( -237 )KJ       = - 49 KJ of useful workcan be obtained.         

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