The reaction 4NH 3 (g) + 5O 2 (g)-----> 4NO(g) + 6H 2 O goes to 100%completion.

Question

The reaction 4NH3(g) + 5O2(g)-----> 4NO(g) + 6H2O goes to 100%completion. If you react 80 molecules of NH3 and90 molecules of O2, how many totalmolecules will be present at completion? This is what I got by comparing the ratio of moles. 72 molecules of ammonia will react with 90 molecules ofO2, producing 72 molecules of NO and 108 molecules ofH2O, leaving 8 molecules of ammonia unreacted. Therefore (72+108+8) = 188 Therefore, 188 molecules will be present at completion. Am I on the right track? Thank you, will ratelifesaver! The reaction 4NH3(g) + 5O2(g)-----> 4NO(g) + 6H2O goes to 100%completion. If you react 80 molecules of NH3 and90 molecules of O2, how many totalmolecules will be present at completion? This is what I got by comparing the ratio of moles. 72 molecules of ammonia will react with 90 molecules ofO2, producing 72 molecules of NO and 108 molecules ofH2O, leaving 8 molecules of ammonia unreacted. Therefore (72+108+8) = 188 Therefore, 188 molecules will be present at completion. Am I on the right track? Thank you, will ratelifesaver!

Explanation / Answer

Your on right track4NH3(g) + 5O2(g)-----> 4NO(g) + 6H2O 4 moles of NH3 reacts with 5 moles of O2 produces 4 moles ofNO& 6 moles of H2O 90 moles of O2 requires X moles of NH3 X = ( 4*90 ) / 5     = 72 moles of NH3 So, (80 - 72 ) = 8 moles of NH3 is left unreacted 72 moles of NH3 produces 72 moles of NO &{ ( 6 * 72 ) / 4 } = 108 moles of H2O So, total molecules will be present atcompletion is = 72 moles of NO + 108 moles of H2O + 8 moles ofunreacted NH3                                                                              = 188 moles 90 moles of O2 requires X moles of NH3 X = ( 4*90 ) / 5     = 72 moles of NH3 So, (80 - 72 ) = 8 moles of NH3 is left unreacted 72 moles of NH3 produces 72 moles of NO &{ ( 6 * 72 ) / 4 } = 108 moles of H2O So, total molecules will be present atcompletion is = 72 moles of NO + 108 moles of H2O + 8 moles ofunreacted NH3                                                                              = 188 moles

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