Determine freezing point depression of the solution, calculatethe molality of te

Question

Determine freezing point depression of the solution, calculatethe molality of teh solution and molar mass of the solute. A solution is prepared by dissolving 138.50g of sucrose, a nonelectrolyte, in 250.0g of deionized water. The freezing point ofthe solution was determined experimentally to be -3.00celcius Determine freezing point depression of the solution, calculatethe molality of teh solution and molar mass of the solute. A solution is prepared by dissolving 138.50g of sucrose, a nonelectrolyte, in 250.0g of deionized water. The freezing point ofthe solution was determined experimentally to be -3.00celcius

Explanation / Answer

Molar mass or molecular weight is determing by looking at the MW ofeach contituent atom and adding them together. MM of sucrose = 342.3 g/mol molality = mols of solute / kg of solvent mols of sucrose = 138.5g sucrose / 342.3 g/mol = 0.405 mols ofsucrose molality = 0.405 mols sucrose / 0.250 kg water = 1.62 m sucrose Equation for freezing point depression: change in temperature= Kf*m Kf is a constant that can be found in tables or online. TheKf for water is 1.86 *C/m. m is the molality of the solution. (1.86)(1.62) = 3.01 degrees C This agrees with the experimentally derived value.

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