1. how many millilitersof CHCL3 are needed to prepare a 2.5% v/v solution in 500

Question

1. how many millilitersof CHCL3 are needed to prepare a 2.5% v/v solution in 500 mL ofmethanol? 2.If a 250 mL solution of ethanol in water is prepared with 4mL of absolute ethanol, what will be the concentration of ethanolin % v/v? 3.What molarity of HCL is needed so that 5 mL diluted to 300mL will yield 0.2M? 1. how many millilitersof CHCL3 are needed to prepare a 2.5% v/v solution in 500 mL ofmethanol? 2.If a 250 mL solution of ethanol in water is prepared with 4mL of absolute ethanol, what will be the concentration of ethanolin % v/v? 3.What molarity of HCL is needed so that 5 mL diluted to 300mL will yield 0.2M?

Explanation / Answer

Formula:                   % volume = Volume of solute * 100 % / Volume ofsolution a)               2.5 %      = Volume of CHCl3 *100 % / 500 mL Volume ofCHCl3       = 500 mL * 2.5/ 100                                    = 12.5 mL b)              % volume = 4 mL * 100 % / 250 mL                                    =   1.6 % c)    Molarity of HCl   = 0.3 L* 0.2 M / 0.005 L                                   =12 M

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