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PART 1: To obtain the same antifreeze protection requires 76g ofpropylene glycol

ID: 684718 • Letter: P

Question

PART 1: To obtain the same antifreeze protection requires 76g ofpropylene glycol to replace each 62g of ethylene glycol. Calculate the mass of propylene glycol required to replace3.00 gallons of ethylene glycol. The density of ethyleneglycol is 1.12 g/mL.
PART 2: Calculate the volume of propylene glycol, in gallons, toproduce the same antifreeze protection as 3.00 gallons of ethyleneglycol. To obtain the same antifreeze protection requires 76g ofpropylene glycol to replace each 62g of ethylene glycol. Calculate the mass of propylene glycol required to replace3.00 gallons of ethylene glycol. The density of ethyleneglycol is 1.12 g/mL.
PART 2: Calculate the volume of propylene glycol, in gallons, toproduce the same antifreeze protection as 3.00 gallons of ethyleneglycol.

Explanation / Answer

3gal ethylene glycol*(3.785 L/gal) *(1000mL/1L)*(1.12g ethylene glycol/ mL) * (76g propylene glycol/62 gethylene glycol) = 15589.3161 grams propylene glycol = 1.56 x 104grams PART 2: propylene glycol density = 1.036 g/mL 1.56 e4 grams *( 1 mL/1.036 g) *(1 L/1000 mL)*(1 gal/ 3.785 L) =3.98 gallons propylene glycol