How do u find the limiting reagent of BaCl2 +H2SO4 > BaSO4+ 2HCl My assigned Vol

Question

How do u find the limiting reagent of BaCl2 +H2SO4 > BaSO4+ 2HCl My assigned Vol. of BaCl2 was 15 mL the actual mass of BaSO4 is .92g ***I dont know if these values may be any help but here theyare
There is .20 M barium chloride
.60 M Sulfuric acid
1 M hydrochloric acid
I added 15ml of BaCl2 into a solution that contained 5ml ofsulfuric acid & 5ml of hcl How do u find the limiting reagent of BaCl2 +H2SO4 > BaSO4+ 2HCl My assigned Vol. of BaCl2 was 15 mL the actual mass of BaSO4 is .92g ***I dont know if these values may be any help but here theyare
There is .20 M barium chloride
.60 M Sulfuric acid
1 M hydrochloric acid
I added 15ml of BaCl2 into a solution that contained 5ml ofsulfuric acid & 5ml of hcl How do u find the limiting reagent of BaCl2 +H2SO4 > BaSO4+ 2HCl My assigned Vol. of BaCl2 was 15 mL the actual mass of BaSO4 is .92g ***I dont know if these values may be any help but here theyare
There is .20 M barium chloride
.60 M Sulfuric acid
1 M hydrochloric acid
I added 15ml of BaCl2 into a solution that contained 5ml ofsulfuric acid & 5ml of hcl

Explanation / Answer

Find the starting material, SM, with the LEAST number ofmoles. That will be the LR. 1. Balance the equation 2. You have 15mL of 0.20M BaCl2. mols, n=CV then divide by the coefficient of the balanced chemicalequation 3. You have 5 mL of 0.60M H2SO4 mols, n=CV then divide by the coefficient of the balanced chemicalequation 4. Compare the values for the SMs, whichever is smaller islimiting.

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