How do u do #6? Consider the following reaction at constant P. Use the informati

Question

How do u do #6? Consider the following reaction at constant P. Use the information here to determine the value of Delta S_surr at 298 K. Predict whether or not this reaction will be spontaneous at this temperature. N_2(g) + 2 O_2(g) rightarrow 2 NO_2(g) Delta H = +66.4 kJ Delta S_surr = +223 J/K, reaction is spontaneous spontaneous Delta S_surr = -223 J/K, reaction is not spontaneous Delta S_surr = -66.4 J/K. reaction is not spontaneous Delta S_surr = +2656 kJ/K, reaction is not spontaneous Delta S_surr = -66.4 J/K, it is not possible to predict the spontaneity of this reaction without more information. Consider the following reaction at constant P. Use the information here to determine the value of Delta S_surr at 355 K Predict whether or not this reaction will be spontaneous at this temperature. 2 NO(g) + O-2(g) rightarrow 2 NO_2(g) Delta H = -114 kJ Delta S_surr = +114 kJ/K, reaction is spontaneous Delta S_surr = +114 kJ/K, reaction is not spontaneous

Explanation / Answer

6) dG = dH - TdS

dS = dH/T

with,

dH = +66.4 kJ

T = 298 K

we get,

dSsurr = 66.4 x 1000/298 = 223 J/K

A) dSsurr = +223 J/K, reaction is spontaneous

7) Again using the same formula as was in 6),

dSsurr = -114 x 1000/355 = -321 J/K, reaction is spontaneous

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