N 2 (g) +O 2 (g) =2NO (g) Solution nO2 = (40.90 g O2) / (32.00 mol/g) = 1.278mol

Question

N2(g)+O2(g) =2NO(g)

Explanation / Answer

nO2 = (40.90 g O2) / (32.00 mol/g) = 1.278mol O2 => [N2] = [O2] = 1.278 mol / 490.0 L= 0.002608 M                          N2(g)       +      O2(g)       2NO(g)Initial      0.002608 M      0.002608M               0 M Change   -x                    -x                        +2x Final    (0.002608-x) M   (0.002608-x) M    0.001213 M => 2x = 0.001213 M => x = 0.0006065 M => Concentration of O2 reacted is 0.0006065M We also have the final concentration of N2 &O2: => [N2] = [O2] = 0.002608 M - 0.0006065 M= 0.002002 M Hope this helps!

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