The vapor pressure of ammonia at several differenttemperatures is shown in the f

Question

The vapor pressure of ammonia at several differenttemperatures is shown in the following table. Use the data todetermine the heat of vaporizaion and normal boiling point ofammonia. Temperature (k) Pressure (torr) 200                   65.3 210                   134.3 220                   255.7 230                    456.0 235                   597.0 The vapor pressure of ammonia at several differenttemperatures is shown in the following table. Use the data todetermine the heat of vaporizaion and normal boiling point ofammonia. Temperature (k) Pressure (torr) 200                   65.3 210                   134.3 220                   255.7 230                    456.0 235                   597.0

Explanation / Answer

            According toClasius - clayperon equation ,   ln (P2/P1) = (Hvap / R) ( 1 / T1 -1/T2)                   By substituting the values from the above table we get                         ln ( 134.3 / 65.3) =  (Hvap / 8.314 J/K.mol)( 1 / 200 K - 1/ 210K)                     heat of vapourization   = 25.179kJ                At the boiling point the vapour pressure would become equalto 1 atm                                1 atm = 760 torr              ln (P2 /P1) = (Hvap / R) ( 1 /T1 - 1/T2)               ln ( 760 / 65.3) = (25179 J / 8.314 J/K.mol) ( 1 / 200K - 1/ Tb)                boiling point Tb =  238.68 K                   

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